Hancock

Posted: 24 de January de 2011 in 53cr3t5

9+95*&0 0& &92&9)&: ß0ß %ß)&0? 9@ß (@8&0 %&=ß !*& &(2ß* @ %@((@1!

2&92ß & 2&92ß & 2&92ß @+9)@ 0@+( (&1 &=+3 & 9*9@ ß9(+5ß!!! 4@ß %ß1 @#*)@1 2ß)@ @ 5&92& 0@( @ 0+0 9+95*&0 0& %ß)& @#*)@1::: &* 9@ß !*&1ß 0*+2ß (ß !*&1ß @=5*&0 ß0 !*&0 (+92@ *0@ =+5@@ß::: 0@( &((@( 9*9@ &(2@ß )+(%ß9ß7&+(:::

6ß1ß & 6ß1ß::: %&9(ß &0 (*++)@1-0&::: (&+ !*& @5*&92ß 0@( 9@ß !*&1ß::: !*&1ß @@8@1 ß0 &(2& (ß41+0&92ß::: %@1@1 )& 6ß1@1:::

(+92ß-0& 2@ß (ß:::

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